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SIMPLE HARMONIC MOTION

Updated: Oct 23, 2023

JEE MAIN CHAPTER OVERVIEW

​Chapter Priority

​3 (LOW)

​Number of problems in PYQ

​HIGH

​Difficulty

​MODERATE/HIGH

KEY CONCEPTS FOR JEE MAIN


SIMPLE HARMONIC MOTION FOR IIT JEE MAIN & ADVANCED

FORCE LAW OF SHM


A particle will perform SHM if it is under a force of the form:


F = -kx


Where k is a constant (also called force constant) and ‘x’ is the displacement of the particle from the mean position.


The particle must have a mean position where Fnet = 0


When displaced in positive direction, force is towards negative direction.


When displaced in negative direction, force is towards positive direction.


If particle has mass ‘m’, both equations below are valid


Therefore,



w is the angular frequency [don’t confuse this with angular velocity of circular motion]

‘a’ is the acceleration of the particle.


EQUATION OF MOTION UNDER SHM


Where,


‘x’ is the displacement of the particle from mean position

‘A’ is the amplitude (maximum displacement in positive and negative direction)

'w' is the angular frequency [ don’t confuse this with angular velocity of circular motion

'wt' is the angle inside the sin function => It is called ‘phase’ (Phi). Since time always increases, phase (Phi) always increases with time.



Understanding the motion of a particle under SHM at different phases

RELATION BETWEEN POSITION(X) & PHASE (PHI)


Relations between position of particle in SHM and its phase. IIT JEE PHYSICS SHM.

Time period = Time to complete one whole cycle of oscillation

IMPORTANT FORMULAE FOR SHM


TRY JEE MAIN PYQs


Q. A particle executes SHM between x = +A and x = -A. If the time taken by the particle to go from x = 0 to x = A/2 is 2s; then the time taken to go from x = A/2 to x = A is _________


[Hint: Use the phase and position table given above]


Q. A particle of mass 250g executes SHM under a periodic force F = (-25x) N. The maximum speed of the particle is 4 m/s. Find the amplitude of motion.


[Hint: What is the formula for maximum velocity in SHM? v(max)= Aw]


[If you cannot solve, let us know your doubt at www.savai.co.in or WhatsApp me @ 7982286138, we will send solution.]


ENERGY ASSOCIATED WITH SHM

Total Energy (TE) = Potential Energy (U) + Kinetic Energy (KE)


Therefore,TE is constant [Very important]


Variation of potential energy and kinetic energy with displacement under SHM

Potential Energy as a function of time is given by the function below


This is useful when JEE MAIN questions asking about relation of energy vs time are asked. For example:


TRY JEE MAIN PYQs


Q. Let T be time period of a particle under SHM, when will the slope of the PE vs Time graph be maximum.


[Hint: Differentiate PE equation w.r.t time to get slope. Maximize the slope, find out the angle (phase) and calculate time to reach that phase.]


[If you cannot solve, let us know your doubt at www.savai.co.in or WhatsApp me @ 7982286138, we will send solution.]


GENERAL EQUATION OF SHM


When the particles mean position is not x = 0 but some x = 0 and at time = 0, the particle starts from a general point x = x’.


General Equation of SHM when particle does not start from x=0 at time = 0

EXAMPLES

Equation of motion for a particle under SHM starts from x=A at time = 0


Equation of a particle in SHM when particle at x = 0 at time = 0 and velocity is negative

SHM & TIME PERIOD


FORCE METHOD

Steps:

a. Find Mean position where Fnet = 0

b. Displace particle slightly from mean position

c. Write Force on particle expressed in form of F = -kx


In this case, the time period is

TIME PERIOD OF SPRING UNDER CONSTANT FORCE

Whenever a constant force is applied on a spring, its mean position can differ but time period remains constant.

[m – mass of particle, k – spring constant]

Time period is:


Time period of particle under SHM with spring under constant force (horizontal and vertical gravitational force).  IIT JEE Physics, Simple Harmonic Motion.


Time period of particle under SHM with spring under constant force (pseudo force upward and downward and incline gravitational force).  IIT JEE Physics, Simple Harmonic Motion.

In all cases, mean position will differ but time period will be same. Under acceleration, a constant pseudo force changes mean position but time period is not impacted.


COMMON QUESTION ASKED IN JEE MAIN

Assume that the earth is a solid sphere of uniform density and a tunnel is dug along its diameter throughout the earth. It is found that when a particle is released in the tunnel, the particle executes SHM. The mass of the particle is 100g. The time period of motion will be (approximately) (take g = 10m/s2, radius of earth = 6400km)


Such a question using gravitation and SHM concepts is very common.

Here,

R = Radius of earth; g = acceleration due to gravity.


Try solving it yourself [Hint: What is the gravitational field at a point inside a uniform solid sphere]

[If you cannot solve, let us know your doubt at www.savai.co.in or WhatsApp me @ 7982286138, we will send solution.]



Assume that the earth is a solid sphere of uniform density and a tunnel is dug along its diameter throughout the earth. It is found that when a particle is released in the tunnel, the particle executes SHM. The mass of the particle is 100g. The time period of motion will be (approximately) (take g = 10m/s2, radius of earth = 6400km)

SIMPLE PENDULUM

Simple pendulum is a case of rotational SHM. Given below is the comparison between Linear and Rotational SHM.

Comparison of Linear and Rotational SHM. Time Period of Pendulum

For a simple pendulum,

Remember, the ‘g’ in the equation is g(effective).


Derivation of time period of simple pendulum under SHM

g(effective) – TIME PERIOD

When pendulum inside a lift accelerated (a) upwards

When pendulum inside a lift accelerated (a) downwards

Time period of a pendulum when acceleration vertical. IIT JEE PHYSICS SHM.

When accelerated horizontally (a)



Time period of a pendulum when acceleration horizontal. IIT JEE PHYSICS SHM.
Time period of a pendulum when acceleration horizontal. IIT JEE PHYSICS SHM.

PENDULUM INSIDE A LIQUID

Time period when a pendulum is immersed inside a liquid of density. IIT JEE PHYSICS SHM.

Where is density of liquid and is density of bob attached to pendulum

Derivation of Time period of a liquid under SHM inside a liquid of density. IIT JEE PHYSICS SHM

PHYSICAL PENDULUM

In this, remember perpendicular and parallel axis theorems of moment of inertia

Time period of physical pendulum with moment of inertia I.

I = moment of inertia about hinge

L = distance of centre of mass from hinge point

Time period of a physical pendulum of moment if inertia I and distance of centre of mass as L. IIT JEE PHYSICS SHM..

Keff

Springs in Series and Parallel. IIT JEE PHYSICS SHM.

Series combination: (1/Keff) = (1/K1) + (1/K2) + (1/K3)….


Parallel combination: Keff = K1 + K2 + K3…….



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For any kind of doubts or if you require Physics classes visit www.savai.co.in or WhatsApp me @ 7982286138, we will send solution.]









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